Given a string s of lowercase letters, we need to remove consecutive vowels from the string
Note : Sentence should not contain two consecutive vowels ( a, e, i, o, u).
Examples :
Input: geeks for geeksOutput: geks for geksInput : your article is in queue Output : yor article is in qu
Recommended: Please try your approach on {IDE} first, before moving on to the solution.
Approach: Iterate string using a loop and check for the repetitiveness of vowels in a given sentence and in case if consecutive vowels are found then delete the vowel till coming next consonant and printing the updated string.
Implementation:
C++
// C++ program for printing sentence
// without repetitive vowels
#include <bits/stdc++.h>
using namespace std;
// function which returns True or False
// for occurrence of a vowel
bool is_vow(char c)
{
// this compares vowel with
// character 'c'
return (c == 'a') || (c == 'e') ||
(c == 'i') || (c == 'o') ||
(c == 'u');
}
// function to print resultant string
void removeVowels(string str)
{
// print 1st character
printf("%c", str[0]);
// loop to check for each character
for (int i = 1; str[i]; i++)
// comparison of consecutive characters
if ((!is_vow(str[i - 1])) ||
(!is_vow(str[i])))
printf("%c", str[i]);
}
// Driver Code
int main()
{
char str[] = " geeks for geeks";
removeVowels(str);
}
// This code is contributed by Abhinav96
Java
// Java program for printing sentence
// without repetitive vowels
import java.io.*;
import java.util.*;
import java.lang.*;
class GFG
{
// function which returns
// True or False for
// occurrence of a vowel
static boolean is_vow(char c)
{
// this compares vowel
// with character 'c'
return (c == 'a') || (c == 'e') ||
(c == 'i') || (c == 'o') ||
(c == 'u');
}
// function to print
// resultant string
static void removeVowels(String str)
{
// print 1st character
System.out.print(str.charAt(0));
// loop to check for
// each character
for (int i = 1;
i < str.length(); i++)
// comparison of
// consecutive characters
if ((!is_vow(str.charAt(i - 1))) ||
(!is_vow(str.charAt(i))))
System.out.print(str.charAt(i));
}
// Driver Code
public static void main(String[] args)
{
String str = "geeks for geeks";
removeVowels(str);
}
}
Python3
# Python3 implementation for printing
# sentence without repetitive vowels
# function which returns True or False
# for occurrence of a vowel
def is_vow(c):
# this compares vowel with
# character 'c'
return ((c == 'a') or (c == 'e') or
(c == 'i') or (c == 'o') or
(c == 'u'));
# function to print resultant string
def removeVowels(str):
# print 1st character
print(str[0], end = "");
# loop to check for each character
for i in range(1,len(str)):
# comparison of consecutive
# characters
if ((is_vow(str[i - 1]) != True) or
(is_vow(str[i]) != True)):
print(str[i], end = "");
# Driver code
str= " geeks for geeks";
removeVowels(str);
# This code is contributed by mits
C#
// C# program for printing sentence
// without repetitive vowels
using System;
class GFG
{
// function which returns
// True or False for
// occurrence of a vowel
static bool is_vow(char c)
{
// this compares vowel
// with character 'c'
return (c == 'a') || (c == 'e') ||
(c == 'i') || (c == 'o') ||
(c == 'u');
}
// function to print
// resultant string
static void removeVowels(string str)
{
// print 1st character
Console.Write(str[0]);
// loop to check for
// each character
for (int i = 1; i < str.Length; i++)
// comparison of
// consecutive characters
if ((!is_vow(str[i - 1])) ||
(!is_vow(str[i])))
Console.Write(str[i]);
}
// Driver Code
static void Main()
{
string str = "geeks for geeks";
removeVowels(str);
}
}
// This code is contributed
// by Manish Shaw(manishshaw1)
PHP
<?php
// PHP implementation for printing
// sentence without repetitive vowels
// function which returns True or False
// for occurrence of a vowel
function is_vow($c)
{
// this compares vowel with
// character 'c'
return ($c == 'a') || ($c == 'e') ||
($c == 'i') || ($c == 'o') ||
($c == 'u');
}
// function to print resultant string
function removeVowels($str)
{
// print 1st character
printf($str[0]);
// loop to check for each character
for ($i = 1; $i < strlen($str); $i++)
// comparison of consecutive
// characters
if ((!is_vow($str[$i - 1])) ||
(!is_vow($str[$i])))
printf($str[$i]);
}
// Driver code
$str= " geeks for geeks";
removeVowels($str);
// This code is contributed by mits
?>
Javascript
<script>
// JavaScript program for printing sentence
// without repetitive vowels
// function which returns True or False
// for occurrence of a vowel
function is_vow(c)
{
// this compares vowel with
// character 'c'
return (c == 'a') || (c == 'e') ||
(c == 'i') || (c == 'o') ||
(c == 'u');
}
// function to print resultant string
function removeVowels(str)
{
// print 1st character
document.write(str[0]);
// loop to check for each character
for (let i = 1; i<str.length; i++)
// comparison of consecutive characters
if ((!is_vow(str[i - 1])) ||
(!is_vow(str[i])))
document.write(str[i]);
}
// Driver Code
let str = " geeks for geeks";
removeVowels(str);
// This code is contributed by shinjanpatra
</script>
Output :
geks for geks
Time Complexity: O(n), where n is the length of the string
Space Complexity: O(n), where n is the length of the string
Another approach:- here’s another approach in C++ to remove consecutive vowels from a string using a stack:
- Define a function named isVowel that takes a character as input and returns a boolean value indicating whether the character is a vowel.
- Define a function named removeConsecutiveVowels that takes a string as input and returns a string with all consecutive vowels removed.
- Create a stack named stk to store the characters of the input string.
- Get the length of the input string.
- Loop through each character of the input string by using a for loop.
- Check if the current character is a vowel by calling the isVowel function.
- If the current character is a vowel, check if the stack is not empty and the top of the stack is also a vowel.
- If the conditions in step 8 are satisfied, pop all consecutive vowels from the stack.
- Push the current character onto the stack.
- Construct the result string by popping all elements from the stack.
- Return the result string.
Below is the implementation of the above approach:
C++
#include <iostream>
#include <string>
#include <stack>
using namespace std;
bool isVowel(char c) {
// check if a character is a vowel
return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');
}
string removeConsecutiveVowels(string str) {
stack<char> stk;
int len = str.length();
for (int i = 0; i < len; i++) {
// if current character is a vowel
if (isVowel(str[i])) {
// check if the stack is not empty and the top of the stack is also a vowel
if (!stk.empty() && isVowel(stk.top())) {
// pop all consecutive vowels from the stack
while (!stk.empty() && isVowel(stk.top())) {
stk.pop();
}
}
}
// push the current character onto the stack
stk.push(str[i]);
}
// construct the result string by popping all elements from the stack
string result = "";
while (!stk.empty()) {
result = stk.top() + result;
stk.pop();
}
return result;
}
int main() {
string str = " geeks for geeks";
cout << removeConsecutiveVowels(str) << endl; // expected output: "ltcdsccmmntyfrcdrs"
return 0;
}
Python3
def is_vowel(c):
# check if a character is a vowel
return (c == 'a' or c == 'e' or c == 'i' or c == 'o' or c == 'u' or
c == 'A' or c == 'E' or c == 'I' or c == 'O' or c == 'U')
def remove_consecutive_vowels(s):
stack = []
for c in s:
# if current character is a vowel
if is_vowel(c):
# check if the stack is not empty and the top of the stack is also a vowel
if stack and is_vowel(stack[-1]):
# pop all consecutive vowels from the stack
while stack and is_vowel(stack[-1]):
stack.pop()
# push the current character onto the stack
stack.append(c)
# construct the result string by popping all elements from the stack
result = ""
while stack:
result = stack.pop() + result
return result
# test the function
s = " geeks for geeks"
print(remove_consecutive_vowels(s))
C#
using System;
using System.Collections.Generic;
public class Program {
static bool IsVowel(char c)
{
// check if a character is a vowel
return (c == 'a' || c == 'e' || c == 'i' || c == 'o'
|| c == 'u' || c == 'A' || c == 'E'
|| c == 'I' || c == 'O' || c == 'U');
}
static string RemoveConsecutiveVowels(string str)
{
Stack<char> stk = new Stack<char>();
int len = str.Length;
for (int i = 0; i < len; i++) {
// if current character is a vowel
if (IsVowel(str[i])) {
// check if the stack is not empty and the
// top of the stack is also a vowel
if (stk.Count > 0 && IsVowel(stk.Peek())) {
// pop all consecutive vowels from the
// stack
while (stk.Count > 0
&& IsVowel(stk.Peek())) {
stk.Pop();
}
}
}
// push the current character onto the stack
stk.Push(str[i]);
}
// construct the result string by popping all
// elements from the stack
string result = "";
while (stk.Count > 0) {
result = stk.Peek() + result;
stk.Pop();
}
return result;
}
public static void Main()
{
string str = " geeks for geeks";
Console.WriteLine(RemoveConsecutiveVowels(
str)); // expected output: " gks fr gks"
}
}
// This code is contributed by user_dtewbxkn77n
Javascript
function isVowel(c) {
// check if a character is a vowel
return (c === 'a' || c === 'e' || c === 'i' || c === 'o' || c === 'u' ||
c === 'A' || c === 'E' || c === 'I' || c === 'O' || c === 'U');
}
function removeConsecutiveVowels(str) {
let stk = [];
let len = str.length;
for (let i = 0; i < len; i++)
{
// if current character is a vowel
if (isVowel(str[i]))
{
// check if the stack is not empty and the top of the stack is also a vowel
if (stk.length > 0 && isVowel(stk[stk.length - 1]))
{
// pop all consecutive vowels from the stack
while (stk.length > 0 && isVowel(stk[stk.length - 1])) {
stk.pop();
}
}
}
// push the current character onto the stack
stk.push(str[i]);
}
// construct the result string by popping all elements from the stack
let result = "";
while (stk.length > 0) {
result = stk[stk.length - 1] + result;
stk.pop();
}
return result;
}
let str = " geeks for geeks";
console.log(removeConsecutiveVowels(str));
Java
import java.util.Stack;
public class RemoveConsecutiveVowels {
public static boolean isVowel(char c) {
// check if a character is a vowel
return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');
}
public static String removeConsecutiveVowels(String str) {
Stack<Character> stk = new Stack<>();
int len = str.length();
for (int i = 0; i < len; i++) {
// if current character is a vowel
if (isVowel(str.charAt(i))) {
// check if the stack is not empty and the top of the stack is also a vowel
if (!stk.empty() && isVowel(stk.peek())) {
// pop all consecutive vowels from the stack
while (!stk.empty() && isVowel(stk.peek())) {
stk.pop();
}
}
}
// push the current character onto the stack
stk.push(str.charAt(i));
}
// construct the result string by popping all elements from the stack
StringBuilder result = new StringBuilder();
while (!stk.empty()) {
result.insert(0, stk.peek());
stk.pop();
}
return result.toString();
}
public static void main(String[] args) {
String str = " geeks for geeks";
System.out.println(removeConsecutiveVowels(str)); // expected output: "ltcdsccmmntyfrcdrs"
}
}
// This code is contributed by Prajwal Kandekar
Output
geks for geks
Time Complexity: O(n), where n is the length of the string
The time complexity of the removeConsecutiveVowels function is O(n), where n is the length of the input string. This is because each character of the input string is processed once in the for loop, and all operations inside the loop are constant time operations.
Space Complexity: O(n), where n is the length of the string
The space complexity of the function is O(n), where n is the length of the input string. This is because the size of the stack can be at most the length of the input string, and the result string can also be of the same size as the input string in the worst case.
Another Approach:
This approach works by iterating over the input string and checking each character. If the current character is a vowel, it checks whether the previous character is also a vowel. If the previous character is not a vowel, it appends the current character to the result string. If the previous character is a vowel, it skips over the current character and continues iterating. If the current character is not a vowel, it simply appends it to the result string.
This approach does not use a stack, which can make it simpler and easier to understand. However, it may be slightly less efficient than the stack-based approach, since it needs to check the previous character at each iteration.
C++
#include <iostream>
#include <string>
using namespace std;
bool isVowel(char c) {
// check if a character is a vowel
return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');
}
string removeConsecutiveVowels(string str) {
string result = "";
int len = str.length();
for (int i = 0; i < len; i++) {
// if current character is a vowel
if (isVowel(str[i])) {
// check if the previous character is also a vowel
if (i == 0 || !isVowel(str[i - 1])) {
// if not, append the current character to the result string
result += str[i];
}
} else {
// if the current character is not a vowel, append it to the result string
result += str[i];
}
}
return result;
}
int main() {
string str = " geeks for geeks";
cout << removeConsecutiveVowels(str) << endl; // expected output: " ltcdsccmmntyfrcdrs"
return 0;
}
Output:
geks for geks
Time Complexity: O(n), where n is the length of the input string.
Space Complexity: O(n), where n is the length of the input string.
Constant Space Approach:
The algorithm of the constant space approach for removing repetitive vowels from a sentence is as follows:
- Initialize an empty string called result to store the modified string without repetitive vowels.
- Add the first character of the input string str to the result string.
- Iterate through the remaining characters of the input string from the second character onward.
- For each character at index i in the input string:
- Check if the current character str[i] and the previous character str[i-1] are both vowels using the is_vowel function.
If both characters are vowels, skip adding the current character to the result string, as it is a repetitive vowel.
If either the current character or the previous character is not a vowel, add the current character to the result string.
After iterating through all the characters in the input string, the result string will contain the modified string without repetitive vowels. - Print the result string as the output.
Here is the code of above approach:
C++
#include <iostream>
using namespace std;
bool is_vowel(char c) {
// Convert character to lowercase for case-insensitive comparison
c = tolower(c);
return (c == 'a') || (c == 'e') ||
(c == 'i') || (c == 'o') ||
(c == 'u');
}
void removeVowels(string str) {
// Initialize the result string with the first character of the input string
string result = "";
result += str[0];
// Loop to check for each character starting from the second character
for (int i = 1; i < str.length(); i++) {
// Comparison of consecutive characters
if ((!is_vowel(str[i - 1])) || (!is_vowel(str[i])))
result += str[i];
}
// Print the resultant string
cout << result << endl;
}
int main() {
string str = "geeks for geeks";
removeVowels(str);
return 0;
}
Output
geks for geks
Time Complexity: O(n), where n is the length of the input string.
Auxiliary Space: O(1).
My Personal Notesarrow_drop_up
Last Updated :30 May, 2023
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FAQs
How do you count consecutive vowels in a string? ›
As you move right you ignore all vowels until you get to the 'a' , then ignore the rest until you get to the 'e' , which is the consecutive vowel, and so forth until you get to the 'o' .
How do you remove a vowel from a string? ›- Algorithm. START Step-1: Input the string Step-3: Check vowel presence, if found return TRUE Step-4: Copy it to another array Step-5: Increment the counter Step-6: Print END. ...
- Example. ...
- Output.
- In the first step, we have to convert the string into a character array.
- Calculate the size of the array.
- Call removeDuplicates() method by passing the character array and the length.
- Traverse all the characters present in the character array.
- nidhisingh151199. s=input() ...
- priyarajswarnakar2018. a=input() ...
- Ram. string=input(“Enter string:”) ...
- Ujjawal. arr=['a','e','i','o','u'] ...
- Bibhudutta. str1=str(input()) ...
- 44_Harsh. string = str(input(“enter your string”)) ...
- Souvik. raw = input()
- Input− String[] = “abbbabbbbcdd”
- Output − b.
- Explanation − In the above string, the longest consecutive sequence is of character 'b'. ...
- Input− String[] = “aabbcdeeeeed”
- Output − b.
- string = "Great responsibility";
- print("Duplicate characters in a given string: ");
- #Counts each character present in the string.
- for i in range(0, len(string)):
- count = 1;
- for j in range(i+1, len(string)):
- if(string[i] == string[j] and string[i] != ' '):
- count = count + 1;
To remove all vowels from a string in JavaScript, call the replace() method on the string with this regular expression: /[aeiou]/gi , i.e., str. replace(/[aeiou]/gi, '') . replace() will return a new string where all the vowels in the original string have been replaced with an empty string.
What is it called when you remove the vowels? ›Disemvoweling, disemvowelling (see doubled L), or disemvowelment of a piece of alphabetic text is rewriting it with all the vowel letters elided. Disemvoweling is often used in band and company names.
How do I remove part of a string from a string? ›Remove Characters From a String Using the replace() Method. The String replace() method replaces a character with a new character. You can remove a character from a string by providing the character(s) to replace as the first argument and an empty string as the second argument.
How to extract vowels from a string in Java? ›To find the vowels in a given string, you need to compare every character in the given string with the vowel letters, which can be done through the charAt() and length() methods. charAt() : The charAt() function in Java is used to read characters at a particular index number.
What is a consecutive vowels? ›
This is called hiatus: two consecutive vowel sounds in separate syllables; as opposed to diphthong, two consecutive vowel sounds in the same syllable.
How to remove vowels from a string in C using function? ›- Initialize the variables.
- Accept the input.
- Initialize for loop.
- Check and delete the vowels.
- Store the string without vowels using another for loop.
- Terminate both for loop.
- Print the string without vowels.
filter() function is called with the first argument as filtervowels() function and input list “alphabets” as the second argument. filter() returns a sequence that contains only vowels( both upper and lower letters )Filtered out from the input list.
How do I find a missing vowel in a string? ›You can read a character in a String using the charAt() method. To find the vowels in a given String you need to compare every character in it with the vowel letters.
How do I remove unwanted words from a string in Python? ›In Python you can use the replace() and translate() methods to specify which characters you want to remove from the string and return a new modified string result. It is important to remember that the original string will not be altered because strings are immutable.
How do you count consecutive strings in Java? ›- AAbcde would return 1 (one a after the first a )
- abcde would return 0 (no consecutive count)
- abccd would return 1 (one c after the first c )
- aabccc would return 3 (one a after the first a + two c 's after the first c )
Sliding WIndow Approach
To check if a substring is present in another string can be done in O(N^2). Algorithm: Run a loop from i = 0 till N – 1 and consider a visited array. Run a nested loop from j = i + 1 to N – 1 and check whether the current character S[j] has already been visited.
- Define a string.
- Declare an array freq with the same size as that of string. ...
- Variable minChar represent the minimum occurring character and maxChar represent the maximum occurring character. ...
- Two loops will be used. ...
- Inner loop will compare the selected character with rest of characters present in the string.
The correct answer is 360, although your reasoning is a little off. Think of it this way - imagine you're using the symbols A,B,C1,C2,E,F.
How do you check how many times an element is repeated in an array? ›- Take the size of the array as the user input.
- Declare an array of the asked size.
- Create a count variable to store the count of the duplicate elements in the array and initialize it to zero.
- Use a for loop to fill the elements into the array from the user input.
How do I remove everything from a string except letters? ›
- Take String input from user and store it in a variable called “s”.
- After that use replaceAll() method.
- Write regex to replace character with whitespaces like this s. replaceAll(“[^a-zA-Z]”,””);.
- After that simply print the String after removing character except alphabet.
The replace() method is one of the most commonly used techniques to remove the character from a string in javascript. The replace() method takes two parameters, the first of which is the character to be replaced and the second of which is the character to replace it with.
What is vowel reduction examples? ›The schwa is the most commonly encountered example of a reduced vowel. This vowel occurs in an unstressed word or syllable; examples are the words the, a, the first syllable of about, and the last syllable of sofa. In all such cases, the quality of the vowel is much more central than when the phoneme is stressed.
What is the vowel reduction rule in English? ›Vowel reduction is another important feature of oral English. What does it mean? It means that a vowel sound is pronounced [ə] or [ɪ] instead of another full vowel. For example, the letter <a> in the word about is not pronounced [ɑ] that is present in the word father.
What are the 4 types of vowels? ›From here, we can divide English vowel sounds up into a couple of categories: short vowels, long vowels, diphthongs, vowels before historical R, and weak vowels.
How do I cut a specific part of a string? ›The slice() method extracts a part of a string. The slice() method returns the extracted part in a new string. The slice() method does not change the original string. The start and end parameters specifies the part of the string to extract.
How do you cut string into parts? ›- STEP 1: START.
- STEP 2: DEFINE str = "aaaabbbbcccc"
- STEP 3: DEFINE len.
- STEP 4: SET n =3.
- STEP 5: SET temp = 0.
- STEP 6: chars = len/n.
- STEP 7: DEFINE String[] equalstr.
- STEP 8: IF (len%n!=0) then PRINT ("String can't be divided into equal parts") else go to STEP 9.
Java String isEmpty() Method
The isEmpty() method checks whether a string is empty or not. This method returns true if the string is empty (length() is 0), and false if not.
Using regular expressions to extract any specific word
We can use search() method from re module to find the first occurrence of the word and then we can obtain the word using slicing. re.search() method will take the word to be extracted in regular expression form and the string as input and and returns a re.
Use the replace() method to remove the vowels from a string, e.g. str. replace(/[aeiou]/gi, ''); . The replace() method will return a new string where all vowels in the original string have been replaced by empty strings.
How do you separate vowels and consonants in a string in Java? ›
- Read an input string.
- Convert the string to lower case so that comparisons can be reduced.
- Iterate over it's characters one by one.
- If current character matches with vowels (a, e, i, o, u ) then increment the vCount by 1.
- Else if any character lies between 'a' and 'z', then increment the count for cCount by 1.
In phonology, hiatus, diaeresis (/daɪˈɛrəsəs, -ˈɪər-/), or dieresis describes the occurrence of two separate vowel sounds in adjacent syllables with no intervening consonant. When two vowel sounds instead occur together as part of a single syllable, the result is called a diphthong.
What words have 4 consecutive vowels? ›- Hawaiian.
- Iroquoian.
- Kauai.
- Kilauea.
- Louie.
- Montesquieu.
- Quaoar.
- Rouault.
The word euouae (a mnemonic used in medieval music) is the only word to contain six consecutive vowels, and unsurprisingly is the longest word with no consonants in it.
How to delete all vowels from a sentence in C? ›- int check_vowel(char);
- int main() { ...
- printf("Enter a string to delete vowels\n"); gets(s);
- for (c = 0; s[c] != '\0'; c++) { ...
- t[d] = '\0';
- strcpy(s, t); // We are changing initial string. ...
- printf("String after deleting vowels: %s\n", s);
- return 0;
- Take a string and its substring as input.
- Put each word of the input string into the rows of 2-D array.
- Search for the substring in the rows of 2-D array.
- When the substring is got, then override the current row with next row and so on upto the last row.
- set the count to 0.
- Loop through the string until it reaches a null character.
- Compare each character to the vowels a, e, I o, and u.
- If both are equal, increase the count by one.
- Print the count at the end.
The FILTER function in Excel is used to filter a range of data based on the criteria that you specify. The function belongs to the category of Dynamic Arrays functions. The result is an array of values that automatically spills into a range of cells, starting from the cell where you enter a formula.
How do you filter a vowel in a string in Python? ›For this, we can use the for loop. The for loop is used to pass each vowel through the loop and store the elements in another list. This is the traditional way to filter out the elements present in the list, but with the filter() present in Python the task is done much easier.
What is filter and its function? ›A filter is a circuit capable of passing (or amplifying) certain frequencies while attenuating other frequencies. Thus, a filter can extract important frequencies from signals that also contain undesirable or irrelevant frequencies.
How do you check for vowels? ›
The five letters A , E , I , O and U are called vowels. All other alphabets except these 5 vowels are called consonants.
How do you remove weird characters from a string in Python? ›The replace() method in python can be used to remove specified special characters from the string. The syntax of the replace() method is, The replace() method replaces a character in the string with another character. There is no effect of the replace() method if the character to be replaced is not found in the string.
How to remove list of words from list of strings in Python? ›The remove() method removes the first matching element (which is passed as an argument) from the list. The pop() method removes an element at a given index, and will also return the removed item. You can also use the del keyword in Python to remove an element or slice from a list.
How many words have 4 consecutive vowels? ›After removing plurals and possessives, we have 22 words with four consecutive vowels: Hawaiian. Iroquoian.
How do you count the number of times each word appears in a string? ›The count() method returns the number of occurrences of a substring in the given string.
How do you count vowels in a sentence? ›- Read a sentence from the user.
- Create a variable (count) initialize it with 0;
- Compare each character in the sentence with the characters {'a', 'e', 'i', 'o', 'u' }
- If a match occurs increment the count.
- Finally print count.
Euouae, at six letters long, is the longest English word consisting only of vowels, and, also, the word with the most consecutive vowels. Words with five consecutive vowels include cooeeing and queueing.
How many words have 3 consecutive vowels? ›Hundreds of words have 3 consecutive vowel letters. Some in fact have as many as 5: e.g. queueing, miaoued, cooeeing ("making a loud call to attract attention"), zoaeae ("crustacean larval stages"; above), melopoeiae ("uses of word sounds in poetry") and others.
What are two consecutive vowels called? ›A diphthong is a sound made by combining two vowels, specifically when it starts as one vowel sound and goes to another, like the oy sound in oil.
What is the longest word with consecutive vowels? ›8 Euouae: Euouae is six letters long, but all of the letters are vowels. It holds two Guinness World Records. It's the longest English word composed exclusively of vowels, and it has the most consecutive vowels of any word.
How do you find all occurrences of a word in a string? ›
Using Function
The main() call the check(char *s, char *w) function to find all occurrences of the word in the given string.
To counts the words present in the string, we will iterate through the string and count the spaces present in the string. As each word always ends with a space. If a string starts with a space, then we must not count the first space as it is not preceded by a word.
How do I get each word in a string? ›To find a word in the string, we are using indexOf() and contains() methods of String class. The indexOf() method is used to find an index of the specified substring in the present string.
How do you find the vowels in a string? ›To find the vowels in a given string, you need to compare every character in the given string with the vowel letters, which can be done through the charAt() and length() methods. charAt() : The charAt() function in Java is used to read characters at a particular index number.
What is vowel rule? ›1. Vowels in syllables. Every syllable of every word must have at least one vowel sound. A vowel can stand alone in a syllable, as in u•nit and an•i•mal. It can also be surrounded by consonants, as in jet, nap•kin, and fan•tas•tic.
How do you find vowels in words? ›There are two kinds of letters: vowels and consonants. The letters a, e, i, o, and u are vowels. The letter y is also sometimes a vowel. All the other letters are consonants.